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27-x^2=6x
We move all terms to the left:
27-x^2-(6x)=0
We add all the numbers together, and all the variables
-1x^2-6x+27=0
a = -1; b = -6; c = +27;
Δ = b2-4ac
Δ = -62-4·(-1)·27
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-12}{2*-1}=\frac{-6}{-2} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+12}{2*-1}=\frac{18}{-2} =-9 $
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